WebIn Fig. 10.6, if ∠OAB = 40º, then ∠ACB is equal to : a. 50º b. 40º c. 60º d. 70° Solution: In triangle OAB OA = OB ( radius of a circle) ∠OAB = ∠OBA ∠OBA = 40º (angles opposite to equal sides are equal) Using the angle sum property ∠AOB + ∠OBA + ∠BAO = 180º Substituting the values ∠AOB + 40º + 40º = 180º By further calculation ∠AOB + 80º = 180º Web∠ABC = 20° We know that, “The angle subtended by an arc at the center of a circle is twice the angle subtended by it at remaining part of the circle” According to the theorem, we have, ∠AOC = 2 × ∠ABC = 2 × 20° = 40° Therefore, ∠AOC = 40° Hence, option B is the correct answer. Video transcript
In Fig.10.4, if ∠ABC = 20º, then ∠AOC is equal to: (A
WebGet Answers to all your Questions. In Fig.10.4, if \angle ABC = 20^ {\circ}, then \angle AOC is equal to: (A) 20^ {\circ} (B) 40^ {\circ} (C) 60^ {\circ} (D) 10^ {\circ} WebNov 22, 2024 · Given, ∠ABC = 20° We know that, angle subtended at the centre by an arc is twice the angle subtended by it at the remaining part of circle. ∠AOC = 2∠ABC = 2 x 20° = 40° welcome :) thanks yrr Advertisement New questions in Math Advertisement cfa chalon
In the given figure ∠OAB=110∘ and ∠BCD=130∘ then ∠ABC i
WebWe know that angle subtended by an arc at the center of circle in double the angle subtended at the remaining part. ∠AOC=2∠ABC. ∠AOC=2×20 0. ∠AOC=40 0. Web(In a triangle, exterior angle is equal to the sum of two opposite interior angles) ∴ 130° = 70° + x° ⇒ x° = 130° − 70° = 60° Thus, the measure of angle ∠ABC is 60°. Hence, the correct answer is option (c). WebFeb 19, 2024 · Best answer Given: ∠OBD = 50° Here, AB and CD are the diameters of the circles with centre O. ∠DBC = 90° …. (i) [Angle in the semi-circle] Also, ∠DBC = 50° + ∠OBC 90° = 50° + ∠OBC or ∠OBC = 40° Again, By degree measure theorem: ∠AOC = 2 ∠ABC ∠AOC = 2∠OBC = 2 x 40° = 80° ← Prev Question Next Question → Find MCQs & Mock Test JEE … cfa chambourcy