WebArmstrong Number Program in C++, C Plus Plus CPP with Flowchart. An Armstrong number of three digits is an integer in such a way that the sum of the cubes of all its … WebDec 21, 2024 · Step 1: Take the input. Step 2: Calculate the number of digits and store it as digits. Step 3: Declare a variable sum and initialize to 0. Step 4: For each digit in the number, multiply the same digit for digits times and then add it to the sum. Step 5: Check whether the sum is equal to the input number. Step 6: Print it as an Armstrong number ...
C Program to print Armstrong Numbers between 1 and 500
WebMar 7, 2024 · An Integer number in which the sum of the cubes of its digits is equal to the number itself is called Armstrong Number. For example, 153 is an Armstrong number since 1**3 + 5**3 + 3**3 = 153 Algorithm and Flowchart for Armstrong Number WebNov 18, 2024 · Here we discuss the C Program to Check a Armstrong Number with the help of step by step algorithm. Aim: Write a C Program to Check weather a given number is Armstrong or not. Algorithm: Step 1: … great homeowners insurance companies
Solved Task 2. Write the C++ code only! There will be no
WebJun 19, 2015 · What is Armstrong number? An Armstrong number is a n-digit number that is equal to the sum of the n th power of its digits. For example – 6 = 6 1 = 6 371 = 3 3 + 7 3 + 1 3 = 371. Logic to check Armstrong number. Step by step descriptive logic to check Armstrong number. Input a number from user. Store it in some variable say num. Webanswer (1 of 5): step 1: start step 2: input n step 3: set sum=0,d=n step 4: rem= n%10 step 5: sum= sum+(rem*rem*rem) step 6: n=n/10 step 7: repeat steps 4 to 6, until n>0 step 8: if sum=d print “number is armstrong” else print “number is not armstrong” step 9: stop WebOutput 1. Enter a number: 663 663 is not an Armstrong number. Output 2. Enter a number: 407 407 is an Armstrong number. Here, we ask the user for a number and check if it is an Armstrong number. We need to calculate the sum of the cube of each digit. So, we initialize the sum to 0 and obtain each digit number by using the modulus operator %. great home office printers