C语言 # is not followed by a macro parameter
WebGenerally speaking, the solution is to turn that inside out: use conditional directives to define the macro differently in different cases. That will not work for a generic macro-test … WebAug 2, 2024 · The preprocessor expands macros in all lines except preprocessor directives, lines that have a # as the first non-white-space character. It expands macros in parts of some directives that aren't skipped as part of a conditional compilation. Conditional compilation directives allow you to suppress compilation of parts of a source file.
C语言 # is not followed by a macro parameter
Did you know?
WebMay 25, 2013 · unless preceded by a # or ## preprocessing token or followed by a ## preprocessing token (see below) : #param, ##param, param## In the invocation NAME (mine), the argument is 'mine'; it is fully expanded to 'mine'; it is then substituted into the replacement string: EVALUATOR(mine, VARIABLE) <-- #define NAME ( fun) … WebWhen a macro is expanded, the two tokens on either side of each ‘##’ operator are combined into a single token, which then replaces the ‘##’ and the two original tokens in …
WebMar 25, 2006 · C++ and C). By definition a macro (the part after the #define) ends on the same line. This can be partially ameliorated by the use of continuation lines (where the last character on the physical line is a '\'). You CANNOT put preprocessing conditionals inside a macro, because they have to start a line, and you can't get there without ending the ... WebJun 16, 2024 · If you do not pass a value to the macro when it is invoked, a null value is assigned to the macro variable specified in the %MACRO statement. Here is an example: %macro test ( var1,var2,var3); %put &=var1; %put &=var2; %put &=var3; %mend test; /** Each value corresponds to the position of each variable in the definition.
WebC Macro expansion not working as expected -- getting below error main.c:11:19: error: expected identifier before ‘ (’ token Macro argument is not expanded instead gives … WebIf your macro does not accept parameters, you should use @noparams in your template. If the user macro contains no parameters and does not specify @noparams, then the macro browser will display a free-format text box allowing users to enter undefined parameters. This can be confusing if the macro does not accept parameters.
WebUNUSED 宏. #define UNUSED (x) (void) (x) 我们这样使用这个宏. void f (int x) { UNUSED (x); ... } 使用 void 把 x 做格式转换,这行代码不管在什么编译器上,都可以得心应手,当然了,我们也可以把void改成int,但是这样 …
WebThe C preprocessor is the macro preprocessor for the C, Objective-C and C++ computer programming languages.The preprocessor provides the ability for the inclusion of header files, macro expansions, conditional compilation, and line control.. In many C implementations, it is a separate program invoked by the compiler as the first part of … earls ear lozengesWebOct 29, 2024 · Beginners error # is not followed by a macro param error # is not followed by a macro parameter Oct 28, 2024 at 7:06am AL88 (146) How can I get past this errer … earls dtcWebSep 24, 2015 · 8. You can wrap #ifdef around a macro definition; you can't embed it inside one. Also, you can't directly test whether an argument to a macro is a defined macro. … earlseatWebAug 2, 2024 · The macro name is replaced by a copy of the macro body. If the macro accepts arguments, the actual arguments following the macro name are substituted for … earls easy form tubingWebNov 21, 2024 · You can fix this with an extra "helper" macro: #define MAX_NAME_LEN 15 #define STRINGIFY (s) \ #s #define PRINT_CELL (x) \ printf (" %" STRINGIFY … earlseat collieryWebOct 29, 2024 · The code you've posted doesn't even compile (and you didn't even bother to post it in code tags). earls east reginaWebIt has enhanced features of cpp (or may be cpp is a scaled down version of m4). Specially, it has better support for multi-line macros. It continue to be used in various packages. Worth mentioning that adding a code generation to your code will make it more complex to maintain/debug. define (`CHECK_MACRO', ` #ifdef $1 printf ("defined #$1\n ... earls east